Question

Word ‘UNIVERSITY’ is arranged randomly. Then the

probability that both ‘I’ does not come together, is

• A. $\frac { 3 } { 5 }$
• B. $\frac { 2 } { 5 }$
• C. $\frac { 4 } { 5 }$
• D. $\frac { 1 } { 5 }$

Answer 1

Answer: (C)

$\frac { 4 } { 5 }$

Answer 2

Total number of ways $= \frac { 10 ! } { 2 ! }$

Favourable number of ways for $' I$ come together is 9 !

Thus probability that $' I$ come together

$= \frac { 9 ! \times 2 ! } { 10 ! } = \frac { 2 } { 10 } = \frac { 1 } { 5 }$.

Hence required probability