Question

Without changing the direction of coordinate axes, origin is transferred to (h, k), so that the linear (one degree) terms in the equation (x² + y² – 4x + 6y – 7 = 0 are eliminated. Then the point (h, k) is-

• A. (3, 2)
• B. (–3, 2)
• C. (2, –3)
• D. None of these

Answer 1

Answer: (C)

(2, –3)

Answer 2

= $\left( \frac{coeffofx}{- 2},\frac{coeffofy}{- 2} \right)$

= $\left( \frac{- 4}{- 2},\frac{6}{- 2} \right)$ = (2, – 3)