Question

With what minimum acceleration can a fireman slides down a rope while breaking strength of the rope is $\frac{2}{3}$ his weight

• A. $\frac{2}{3}g$
• B. g
• C. $\frac{1}{3}g$
• D. Zero

Answer 1

Answer: (C)

$\frac{1}{3}g$

Answer 2

When fireman slides down, Tension in the rope $T = m(g - a)$

For critical condition m(g – a) = 2/3 mg ⇒ $mg - ma = \frac{2}{3}mg$ ∴ $a = \frac{g}{3}$

So, this is the minimum acceleration by which a fireman can slides down on a rope.