Question
Physics Question on laws of motion
With what maximum acceleration can a fireman slide down a rope whose breaking strength is two third of his weight?
A
3g
B
32g
C
23g
D
2g
Answer
3g
Explanation
Solution
Net downward force on fireman is
ma=mg−T
As Tmin=32mg
∴mamax=mg−32mg
or amax=3g