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Question: With t taken in seconds and I taken in Amp, the variation of I follows the equation \[t^{2}\text{ +...

With t taken in seconds and I taken in Amp, the variation of I follows the equation

t2 + I2 = 25t^{2}\text{ + }\text{I}^{2}\text{ = 25}

what amount of Ag will be electrodeposited with this current flowing in the interval 0–5 second ? (Ag – 108)

A

22 mg

B

66 mg

C

77 mg

D

88 mg

Answer

22 mg

Explanation

Solution

Q =π(25)4 C =π×254×96500 F∴\text{Q =}\frac{\pi\left( \text{25} \right)}{4}\text{ C =}\frac{\pi \times \text{25}}{4 \times \text{96500}}\text{ F}\therefore

m = 1081 ×π×254×96500 g = 0.02197 g = 21.97 mg ∼‾ 22 mg\text{m = }\frac{\text{108}}{1}\text{ }\text{×}\frac{\pi \times \text{25}}{4 \times \text{96500}}\text{ g = 0.02197 g = 21.97 mg }\underline{\sim}\text{ 22 mg}