Question

Why is $F_2$ the strongest oxidizing agent (among halogens) although electron affinity of $Cl_2$ is higher than $F_2$ ?

• A. Low enthalpy of dissociation and high free energy of hydration
• B. Low enthalpy of dissociation
• C. High free energy of hydration
• D. High electronegativity and low free energy of hydration

Answer 1

Answer: (A)

Low enthalpy of dissociation and high free energy of hydration

Answer 2

$F_{2}$ is strongest oxidising agent due to its low enthalpy of dissociation as $F?F$ bond is weak and high enthalpy of hydration of small $F^{-}$ ion