Question

Why is area inversely Proportional to resistance?

Answer 1

Due to the collision of the charged particles or electrons, the resistance of the current-carrying conductor occurs.
When we increase the cross-sectional area space between the charged particles gets increased. In this context the collisions increase. The resistance decreases when the area increases here they are inversely proportional to each other.

Complete step-by-step solution:
The resistance is opposite to the flow of current, it gets varied depending on the hence the resistance can be written as follows,
$R = \dfrac{{\rho L}}{A}$
Here,
$\rho$is the resistivity
$L$ is the length
$A$ is the cross-sectional area.
Resistance is directly proportional to the specific resistance and conductor length. Here if the resistivity and length increase then the resistance also increases.
Generally, The resistance is always inversely proportional to the cross-sectional area of the conductor. Here if the conductor has a bigger cross-sectional area then the resistance will be decreased.
Here this can be written as follows,
$R\alpha \dfrac{1}{A}$
When the thickness increases the movement becomes little free hence the charge movement becomes possible here the resistance decreases.
The relationship between the resistance and the area of the cross-section is inversely proportional to each other.
Finally, when we increase the area the charged particles also get increased so the collision also increases. This is how the resistance decreases when we increase the area.

Note: The resistance depends on the material length, cross-section, and temperature.
When the cross-section increases the surface area of the wire increases. The surface area leads to the flow of electrons.
Hence the flow of electrons happens easily and resistance will decrease.