Question
Question: Why does chromium form \[C{r^{ + 2}}\] ion?...
Why does chromium form Cr+2 ion?
Solution
In the case of transition elements, the (−d) orbitals start filling successively. Common electronic configuration of transition elements is (n−1)d1−10ns1−2. Chromium elements are transition elements and have transition metals properties.
Complete answer:
As we know the atomic number of chromium elements is 24 and electronic configuration is [Ar]3d54s1. From the electronic configuration of chromium, we can see that it has a half filled (−d) orbital which impart additional stability to the chromium atom.
Transition metals have the characteristic to show more than one oxidation state due to participation of inner (n−1)d electrons. The most common oxidation state exhibited by transition metals of the first row is (+2) which is shown due to loss of a pair of electrons or two electrons present in 4s orbital. As we move from scandium to titanium the strength of 3d orbitals increases and becomes more stable due to this reason electrons are removed from 4s orbital to give an oxidation number of (+2).
The most common oxidation states shown by chromium elements are +2,+3,+4,+5,+6 due to availability of 4s and (n−1)d electrons. Out of all these oxidation numbers, only a few compounds of oxidation number +1,+4,+5 are found to be stable in nature. Chromium atoms usually form chromate and dichromate ions.
⇒ Due to higher stability of 3d orbital of chromium due to half-filled orbital, electrons are removed from its 4s orbital therefore, it easily form stable Cr+2 ions.
Note:
Chromium element has exceptionally high magnitude of ionization enthalpy due to extra stability of half filled (−d) orbital. Higher oxidation state of any transition metal is calculated by adding its outer (s) and (n−1)d electrons. Compounds of chromium are also used as a catalyst during many chemical reactions.