Question
Physics Question on Youngs double slit experiment
White light is used to illuminate the two slits in a Young's double slit experiment. The separation between the slits is b and the screen is at a distance d (>> b) from the slits. At a point on the screen directly in front of one of the slits, certain wavelengths are missing. Some of these missing wavelengths are
λ=b2/d
λ=2b2/d
λ=b2/3d
λ=2b2/3d
λ=b2/3d
Solution
At P (directly infront of S1 ) y = b / 2
∴ Path difference,
ΔX=S2P−S1P=dy.(b)=d(2b)(b)=2db2
Those wavelengths will be missing for which
\hspace25mm \Delta X=\frac{\lambda_1}{2},\frac{3 \lambda_2}{2},\frac{5 \lambda_3}{2}...
\therefore \hspace25mm \lambda_1=2 \Delta x=\frac{b^2}{d}
\hspace25mm \lambda_2=\frac{2 \Delta x}{3}=\frac{b^2}{3d}
\hspace25mm \lambda_3=\frac{2 \Delta x}{5}=\frac{b^2}{5d}
∴ Correct options are (a) and (c).