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Question

Question: While measuring internal resistance of cell a student finds null point at 72.0 cm with cell in circu...

While measuring internal resistance of cell a student finds null point at 72.0 cm with cell in circuit. He introduces resistance of 6 Ω from shunt resistance box. The balance point shifts to 60.0 cm. What will be internal resistance of cell?

A

1.5 Ω

B

1.2 Ω

C

1.3 Ω

D

1.4 Ω

Answer

1.2 Ω

Explanation

Solution

r = (72601)\left( \frac{72}{60} - 1 \right)× 6 = 12×660\frac{12 \times 6}{60} = 1.2 Ω