Question

While charging the lead storage battery

• A. $PbSO_4$ on anode is reduced to $Pb$
• B. $PbSO_4$ on cathode is reduced to $Pb$
• C. $PbSO_4$ on cathode is oxidized to $Pb$
• D. $PbSO_4$ on anode is oxidized to $PbO_2$

Answer 1

Answer: (D)

$PbSO_4$ on anode is oxidized to $PbO_2$

Answer 2

The cell reactions during charging of lead storage battery are
At anode
$PbSO_{4}\left(s\right)+ 2e^{-} \to Pb\left(s\right)+ SO^{2-}_{4}\left(aq\right)$
At cathode
$PbSO_{4}\left(s\right)+ 2H_{2}O\left(l\right) \to PbO_{2}\left(s\right)+ SO^{2-}_{4}\left(aq\right) + 4H^{+} \left(aq\right)+2e^{-}$
So, $PbSO_4$ at the anode is reduced to $Pb$.

During charging, PbO2 is formed at the anode from PbSO4 (oxidation of Pb ion) and Pb is formed at the cathode from PbSO4 (reduction of Pb ion).

Therefore Options B and D are the correct answers.

Discover More From Chapter:Electrochemistry