Question

Which would exhibit ionisation isomerism.

• A. $\left\lbrack Cr\left( NH_{3} \right)_{6} \right\rbrack Cl_{3}$
• B. $\left\lbrack Co\left( NH_{3} \right)_{5}Br \right\rbrack SO_{4}$
• C. $\left\lbrack Cr(en)_{2}Cl_{2} \right\rbrack$
• D. $\left\lbrack Cr(en)_{3}Cl_{3} \right\rbrack$

Answer 1

Answer: (B)

$\left\lbrack Co\left( NH_{3} \right)_{5}Br \right\rbrack SO_{4}$

Answer 2

The compound which has same composition but give different ions in solution, show ionization. So $\lbrack Co(NH_{3})_{5}Br\rbrack SO_{4}$is ionization isomer.

$\lbrack Co(NH_{3})_{5}Br\rbrack SO_{4}$ $\rightleftharpoons$ $\lbrack Co(NH_{3})_{5}Br\rbrack^{2 +} + SO_{4}^{2 -}$

$\lbrack Co(NH_{3})_{5}SO_{4}\rbrack Br$ $\rightleftharpoons$ $\lbrack Co(NH_{3})SO_{4}\rbrack^{+} + Br^{-}$.