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Chemistry Question on Aldehydes, Ketones and Carboxylic Acids

Which will undergo fastest 8282 substitution reaction when treated with NaOHNaOH?

A

H5C2−CC∣H3H∣−BrH_5C_2 - \underset{\overset{|}{H}}{\overset{\underset{|}{C}H_3}{C}} - Br

B

CH3−CC∣H3C∣H3−BrCH_3 - \underset{\overset{|}{C}H_3}{\overset{\underset{|}{C}H_3}{C}} - Br

C

H−CC∣H3C2∣H5−BrH - \underset{\overset{|}{C_2}H_5}{\overset{\underset{|}{C}H_3}{C}} - Br

D

H−CH∣Br∣−CH2−CH2−CH3H - \underset{\overset{|}{Br}}{\overset{\underset{|}{H}}{C}} - CH_2 - CH_2 - CH_3

Answer

H−CH∣Br∣−CH2−CH2−CH3H - \underset{\overset{|}{Br}}{\overset{\underset{|}{H}}{C}} - CH_2 - CH_2 - CH_3

Explanation

Solution

The overall order of reactivity in SN2S_N^{2} reactions is Methyl halides > primary halides > secondary halides > tertiary halides. Thus, among the given compounds primary alkyl halides undergo So reaction most rapidly.