Question

Which type of hydridisation is shown by carbon atoms from left to right in the given compound:

$CH_{2} = CH - C \equiv N?$

• A. $sp^{2},sp^{2},sp$
• B. $sp^{2},sp,sp$
• C. $sp,sp^{2},sp^{3}$
• D. $sp^{3},sp^{2},sp$

Answer 1

Answer: (A)

$sp^{2},sp^{2},sp$

Answer 2

: $sp^{2}sp^{2}sp$

$CH_{2} = CH - C \equiv N$