Question
Chemistry Question on Structure of atom
Which transition in the hydrogen spectrum would have the same wavelength as the Balmer type transition from n=4 to n=2 of He+spectrum
A
n=1 to n=3
B
n=1 to n=2
C
n=2 to n=1
D
n=3 to n=4
Answer
n=2 to n=1
Explanation
Solution
He+ion :
λ(H)1=R(1)2[n121−n221]
λ(He+)1=R(2)2[221−421]
Given λ(H)=λ(He+)
R(1)2[n121−n221]=R(4)[221−421]
n121−n221=121−221
On comparing n1=1&n2=2