Question

Which transition emits photons of maximum frequency?
A.${2^{nd}}$ spectral line of Balmer series
B.${2^{nd}}$ spectral line of Paschen series
C.${5^{th}}$ spectral line of Humphery series
D.${1^{st}}$ spectral line of Lyman series

Answer 1

According to the hydrogen spectrum series, the photons undergo transitions and emit energy. The frequency can be determined from the transition. Based on the transition from one orbit to another orbit different series were named. Humphery series is the series that can undergo transition from ${6^{th}}$ energy level to higher energy levels.

Complete answer:
Niels Bohr discovered the hydrogen spectrum based on the transition from one energy level to different energy levels. He named the different series like the Lymann, Balmer, Paschen, Brackett, Pfund and Humphery series.
The formula for the frequency of different transitions were given as:
$\vartheta = {R_c}\left[ {\dfrac{1}{{{n_1}^2}} - \dfrac{1}{{{n_2}^2}}} \right]$
Where $\vartheta$ is the frequency
${R_c}$ is the Rydberg constant
${n_1}$ is the lower energy level from where the transition occur
${n_2}$ is the higher energy level from where the transition occur
In the given options, Humphery series means the transition occurs from the ${6^{th}}$ energy level to higher energy levels. As it is mentioned as ${5^{th}}$ spectral line the transition occurs from energy level $6$ to energy level $11$. As the Rydberg constant is a constant value. It has a high value of frequency.
So, option (C) is the correct answer.

Note:
Lymann series corresponds to the transition from energy level from $1$ and Balmer series corresponds to the transition from energy level from $2$ Paschen series corresponds to the transition from energy level from $3$, Brackett series corresponds to the transition from energy level from $4$ , Pfund series corresponds to the transition from energy level from $5$ and Humphery series corresponds to the transition from energy level from $6$ .