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Question

Question: Which term of the G.P. \(2,8,32,...\) is \(512\)?...

Which term of the G.P. 2,8,32,...2,8,32,... is 512512?

Explanation

Solution

First we will find the first term and common ratio of the given G.P. Then we assume the term we have to find to be the nth term. Now, we can use the formula of nth term which gives the relation between the first term, common ratio, and nth term of the G.P and is given as-
Tn=arn1\Rightarrow {{\text{T}}_{\text{n}}} = a{r^{n - 1}}
Here, ‘a’ is the first term of the series, r is the common ratio and n is the nth term of the series. Put the given values and solve the required equation.

Complete step-by-step answer:
Here, the given series is 2,8,32,...2,8,32,... which is in G.P.
We have to find the term whose value is 512512 in this series.
Here, the first term ‘a’=22
Common ratio r=82=328=4\dfrac{8}{2} = \dfrac{{32}}{8} = 4
Let the nth{{\text{n}}^{{\text{th}}}} term be 512512
Now we only need to find n.
We know the formula of nth{{\text{n}}^{{\text{th}}}} term is given as-
Tn=arn1\Rightarrow {{\text{T}}_{\text{n}}} = a{r^{n - 1}}
Here, ‘a’ is the first term of the series, r is the common ratio and n is the nth term of the series.
On putting, the given values in the above formula, we get-
512=2(4)n1\Rightarrow {\text{512}} = 2{\left( 4 \right)^{n - 1}}
On solving, we get-
5122=(4)n1\Rightarrow \dfrac{{{\text{512}}}}{2} = {\left( 4 \right)^{n - 1}}
On dividing the numerator by denominator on the left side, we get-
256=(4)n1\Rightarrow 256 = {\left( 4 \right)^{n - 1}}
Now we will find the factors of 256256 so that we can write it in terms of base 44 so we can write 256=4×4×4×4=44256 = 4 \times 4 \times 4 \times 4 = {4^4} then, we get-
44=(4)n1\Rightarrow {4^4} = {\left( 4 \right)^{n - 1}}
Since here the base on both sides is the same so the power of the base should also be equal on both sides. So on comparing powers, we get-
4=n1\Rightarrow 4 = n - 1
On solving, we get-
n=4+1\Rightarrow n = 4 + 1
On further solving, we get-
n=5\Rightarrow n = 5
So here the nth term is 5th{5^{{\text{th}}}} term.
Hence, 512512 is 5th{5^{{\text{th}}}} term of the given G.P. series.

Note: In this type of question, we assume the value of the term we have to find to be the nth term so that we can easily find the value of n using the formula of the nth term in the G.P. series. We can also find terms using this formula provided that we know the value of a, r and n.