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Question: Which term of the A.P \(150\) , \(147\) , \(144\) ,…… is its first negative term?...

Which term of the A.P 150150 , 147147 , 144144 ,…… is its first negative term?

Explanation

Solution

In this problem we need to find which term of the given A.P is the first negative term. So we will first consider the given A.P and compare it with a0{{a}_{0}} , a1{{a}_{1}} , a2{{a}_{2}} ,….. and calculate the value of common difference dd which is given by a1a0{{a}_{1}}-{{a}_{0}} or a2a1{{a}_{2}}-{{a}_{1}} . Now we will first check whether the given A.P has a zero value or not by using the formula an=a0+(n1)d{{a}_{n}}={{a}_{0}}+\left( n-1 \right)d . In this formula we will substitute an=0{{a}_{n}}=0 and calculate the value of nn by using basic mathematical operations. If we get the nnvalue as a natural number, then the upcoming term in the A.P is the first negative term.

Complete step by step answer:
Given Arithmetic Progression is 150150 , 147147 , 144144 ,……
Comparing the above Arithmetic Progression with a0{{a}_{0}} , a1{{a}_{1}} , a2{{a}_{2}} ,….., then we will have
a0=150{{a}_{0}}=150 , a1=147{{a}_{1}}=147 , a2=144{{a}_{2}}=144 .
Now the common difference dd of the progression is equal to the difference between the two successive terms, then we will get
d=a1a0 or a2a1 d=147150 or 144147 d=3 \begin{aligned} & d={{a}_{1}}-{{a}_{0}}\text{ or }{{a}_{2}}-{{a}_{1}} \\\ & \Rightarrow d=147-150\,\text{ or }144-147 \\\ & \Rightarrow d=-3 \\\ \end{aligned}
We are going to check whether the given Arithmetic Progression has 00 or not by substituting an=0{{a}_{n}}=0 in the formula an=a0+(n1)d{{a}_{n}}={{a}_{0}}+\left( n-1 \right)d, then we will get
0=150+(n1)(3)0=150+\left( n-1 \right)\left( -3 \right)
Simplifying the above equation by applying basic mathematical operations, then we will have
0=150(n1)3 3(n1)=150 n1=1503 n=50+1 n=51 \begin{aligned} & 0=150-\left( n-1 \right)3 \\\ & \Rightarrow 3\left( n-1 \right)=150 \\\ & \Rightarrow n-1=\dfrac{150}{3} \\\ & \Rightarrow n=50+1 \\\ & \Rightarrow n=51 \\\ \end{aligned}
From the above value we can say that 51st{{51}^{st}} term of the given Arithmetic Progression is zero. So the next term which is 52nd(51+1){{52}^{nd}}\left( 51+1 \right) terms is definitely the first negative term of the given Arithmetic Progression.

Note: In this problem when we are checking whether the given progression has zero or not. We have the value of nn as 5151 which is a natural number. There is no guarantee that each progression has zero or for each progression we can get the value of nnas a natural number. In some cases we may get a fraction also. In that case we will consider nnvalue to the nearest natural number and check whether it is a negative number or not.