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Question: Which term of \[37,32,27\ \ldots\] is \[- 103\] ? A. \[30\] B. \[29\] C. \[28\] D. \[27\]...

Which term of 37,32,27 37,32,27\ \ldots is 103- 103 ?
A. 3030
B. 2929
C. 2828
D. 2727

Explanation

Solution

In this question, we need to find which term of the given series 37,32,27 37,32,27\ \ldots is 103- 103 . On observing the given sequence, it is an arithmetic progression. It is nothing but a sequence where the difference between the consecutive terms are the same. From the given series, we can find the first term (a)(a) and the common difference (d)(d) . Then , by using the formula of arithmetic progression, we can easily find nn. Here an is the term for which we need to find the value of nn, which is given as 103- 103.

Formula used :
The Formula used to find the nth terms in arithmetic progression is
an= a +(n1)da_{n} = \ a\ + \left( n – 1 \right)d
Where aa is the first term
dd is the common difference
nn is the number of term
ana_{n} is the nthn^{\text{th}} term

Complete answer:
Given , 37,32,27,37,32,27,\ldots
Here we need to find which term of the given series 37,32,27 37,32,27\ \ldots is 103- 103 .
Here a=37a = 37 and d=(3237)d = (32 – 37) which is equal to 5- 5 .
The formula used to find the nthn^{\text{th}} terms in arithmetic progression is an= a+(n1)da_{n} = \ a + \left( n – 1 \right)d
Given that ana_{n} is 103- 103 .
Now on substituting the known values,
We get,
 103=37+(n1)(5)\Rightarrow \ - 103 = 37 + (n – 1)( - 5)
On simplifying,
We get,
103=37+(5n+5)- 103 = 37 + ( - 5n + 5)
On removing the parentheses,
We get,
103=375n+5- 103 = 37 – 5n + 5
Now on simplifying,
We get,
5n=103+37+55n = 103 + 37 + 5
On further simplifying,
We get,
5n=1455n = 145
On dividing both sides by 55 ,
We get,
 n=1455\Rightarrow \ n = \dfrac{145}{5}
On simplifying,
We get,
 n=29\Rightarrow \ n = 29
Thus , 29th29^{\text{th}} term in the AP series is 103- 103 .
Final answer :
29th29^{\text{th}} term in series 37,32,27 37,32,27\ \ldots is 103- 103 .
Option B).2929 is the correct answer.

Therefore, the correct option is B

Note: In order to solve these types of questions, we should have a strong grip over arithmetic series. We should be very careful in choosing the correct formula because there is the chance of making mistakes in interchanging the formula of finding term and summation of term. If we try to solve this sum with the formula Sn=n2(a+l) S_{n} = \dfrac{n}{2}\left( a + l \right)\ where ll is the last term of the series , then our answer will be totally different and can get confused.