Question

Which statement is incorrect?

• A. $Ni(CO)_4$-tetrahedral, paramagnetic
• B. $[Ni(CN)_4]^{2-}$-square planar, diamagnetic
• C. $Ni(CO)_4$-tetrahedral, diamagnetic
• D. $[Ni(Cl)_4]^{2-}$ tetrahedral, paramagnetic

Answer 1

Answer: (A)

$Ni(CO)_4$-tetrahedral, paramagnetic

Answer 2

In $Ni(CO)_4$, Ni has zero oxidation state. It is $sp^3$ hybridised. $Ni(CO)_4 \rightarrow$.
Hence, it has no unpaired electron so, it shows the property of diamagnetism and has tetrahedral structure.