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Question: : Which solution makes the white precipitate of silver chloride soluble in it?...

: Which solution makes the white precipitate of silver chloride soluble in it?

Explanation

Solution

Hint : Precipitate is the insoluble ionic substance that is left behind in the reaction mixture due to the combination of anions and cations along with the products. To make a precipitate soluble it has to form a salt with the solvent. If the precipitate salt is formed, the precipitate is soluble.

Complete Step By Step Answer:
The reaction between Potassium chloride (KCl) and silver nitrate ( AgNO3AgN{{O}_{3}} ) results in the formation of Silver nitrate (AgCl) as the precipitate. The precipitation reaction is given as below:
AgNO3(aq) + KCl(aq) → AgCl(precipitate) + KNO3(aq)AgN{{O}_{3}}_{\left( aq \right)}\text{ }+\text{ }KC{{l}_{\left( aq \right)}}\text{ }\to \text{ }AgC{{l}_{\left( precipitate \right)}}\text{ }+\text{ }KN{{O}_{3}}_{\left( aq \right)}
The white solid precipitate of Silver chloride is soluble in:
1. Ammonia solution-
AgCl reacts with NH3 to form [Ag(NH3)2]+{{[Ag{{(N{{H}_{3}})}_{2}}]}^{+}} a soluble salt. The reaction is as follows:
AgCl+2NH3→[Ag(NH3)2]++Cl−AgCl + 2NH_3 \to {[Ag(NH_3)_2]^+} + Cl^-
2. Sodium thiosulphate ( S2O2{{S}_{2}}{{O}_{2}} ) solution-
AgCl reacts with S2O2{{S}_{2}}{{O}_{2}} to give [Ag(S2O3)2]3−{{[Ag{{({{S}_{2}}{{O}_{3}})}_{2}}]}_{3}}^{-} as a salt. The reaction is shown below:
AgCl + 2(S2O2)−3→ [Ag(S2O3)2]3− + Cl−AgCl\text{ + 2(}{{S}_{2}}{{O}_{2}}{{)}^{-3}}\to \text{ }{{[Ag{{({{S}_{2}}{{O}_{3}})}_{2}}]}_{3}}^{-}\text{ + C}{{\text{l}}^{-}}
3. KCN solution-
AgCl reacts with CN- or KCN to form [Ag(CN)2]−{{[Ag{{(CN)}_{2}}]}^{-}} salt. The reaction is as follows:
AgCl + 2CN−→ [Ag(CN)2]− + Cl−AgCl\text{ + 2C}{{\text{N}}^{-}}\to \text{ }{{[Ag{{(CN)}_{2}}]}^{-}}\text{ + C}{{\text{l}}^{-}}
4. Concentrated KCl solution-
AgCl forms [AgCl2]−{{[AgC{{l}_{2}}]}^{-}} a soluble complex when it reacts with KCl. The equation is as follows:
AgCl + Cl−→[AgCl2]−AgCl\text{ + C}{{\text{l}}^{-}}\to {{[AgC{{l}_{2}}]}^{-}}
5. Ammonium hydroxide-
Ammonia dissolved in water forms Ammonium Hydroxide. AgCl reacts with NH4OH to give [Ag(NH3)2]Cl\left[ Ag{{\left( N{{H}_{3}} \right)}_{2}} \right]Cl i.e. Diamine silver chloride which is soluble in water.
Thus, AgCl is soluble in the above-given solutions.

Note :
AgCl is a precipitate that becomes soluble when it forms a salt with the compound. It is not directly soluble in water. But if the compound forms a solution in water then AgCl readily dissolves in it. The precipitation reactions help to determine the occurrence of various ions present in a certain solution.