Question

Which one of the followings has maximum number of atoms ?

• A. 1g of Ag(s) [Atomic mass of Ag = 108]
• B. 1g of Mg(s) [Atomic mass of Mg = 24]
• C. 1g of $O_2(g)$ [Atomic mass of O = 16]
• D. 1g of $Li(s)$ [Atomic mass of Li = 7]

Answer 1

Answer: (D)

1g of $Li(s)$ [Atomic mass of Li = 7]

Answer 2

Number of atoms in $1\,g$ of $Li = \frac{1}{7} \times N_A$
$= 0.86 \times 10^{23}$
Number of atoms in $1\, g$ of $Ag = \frac{1}{108} \times N_A$
$= 0.056 \times 10^{23}$
Number of atoms in $1\,g$ of $Mg = \frac{1}{24} \times N_A$
$= 0.25 \times 10^{23}$
Number of atoms in $1\,g$ of $O_2 = \frac{1}{32} \times N_A \times 2$
$= \frac{N_A}{16} = 0.37 \times 10^{23}$
Maximum number of atoms are present in$1\,g$ of $Li$.