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Question

Question: Which one of the following is the differentiation of \(x\) with respect to \(\log x,x > 0\): A. \...

Which one of the following is the differentiation of xx with respect to logx,x>0\log x,x > 0:
A. 1x2\dfrac{1}{{{x^2}}}
B. xx
C. logx\log x
D. ex{e^x}

Explanation

Solution

In the given problem, we are required to differentiate x with respect to logx\log x for x>0x > 0. Since, we have to differentiate a function with respect to another function, we first differentiate both the functions with respect to a simple variable and then divide the results in order to get the final answer. So, we apply the chain rule of differentiation in the process of differentiating x with respect to logx\log x. Derivative of logx\log x with respect to x must be remembered in order to solve the given problem.

Complete step by step answer:
We have to find the derivative of x with respect to logx\log x. So, we have, dxd(logx)\dfrac{{dx}}{{d\left( {\log x} \right)}}. Now, we find the derivative of both the functions with respect to x in numerator and denominator. So, we get,
dxdxd(logx)dx\Rightarrow \dfrac{{\dfrac{{dx}}{{dx}}}}{{\dfrac{{d\left( {\log x} \right)}}{{dx}}}}
Now, we know that the derivative of x with respect to x is 11 and the derivative of logarithmic function with respect to x is (1x)\left( {\dfrac{1}{x}} \right). Hence, we get,
1(1x)\Rightarrow \dfrac{1}{{\left( {\dfrac{1}{x}} \right)}}
So, simplifying the expression, we get,
x\Rightarrow x

So, the derivative of x with respect to logx\log x is xx, for x>0x > 0.

Note: The derivatives of basic and simple functions such as logx\log x must be learned by heart in order to find derivatives of complex composite functions using chain rule of differentiation. The chain rule of differentiation involves differentiating a composite by introducing new unknowns to ease the process and examine the behaviour of function layer by layer. Whenever we have to find the derivative of a function with respect to another function, we first find the derivative of both the functions with the variable so as to ease the process of differentiation and then divide both the results.