Question

Which one of the following is incorrect?
A] The bond order of $\mathop H\nolimits_2$, $\mathop N\nolimits_2$ and $\mathop O\nolimits_2$ follows the order $\mathop N\nolimits_2$>$\mathop O\nolimits_2$ > $\mathop H\nolimits_2$
B] In $CsCl$ lattice, each $Cs$ is surrounded by $\mathop {BCl}\nolimits^ -$ ions
C] The ionic nature of $KCl$, $\mathop {Mgcl}\nolimits_2$ and $\mathop {AlCl}\nolimits_3$ follows the order $KCl$ >$\mathop {Mgcl}\nolimits_2$ > $\mathop {AlCl}\nolimits_3$
D] The central atom of $\mathop {PF}\nolimits_5$, $\mathop {ClF}\nolimits_5$, and $\mathop {XeF}\nolimits_2$ have $\mathop {Sp}\nolimits^3 d$ hybridization.

Answer 1

In diatomic molecules, bond order is usually defined as the number of bonds formed between the two atoms. The ionic nature of a substance increases as the charge on it increases. Lattice is defined as the arrangement of atoms in the form of regular arrangement.

Complete step by step answer: A] The bond order of $\mathop H\nolimits_2$, $\mathop N\nolimits_2$and $\mathop O\nolimits_2$ follows the order $\mathop N\nolimits_2$>$\mathop O\nolimits_2$ > $\mathop H\nolimits_2$:- as there are single bond present between dihydrogen $\mathop H\nolimits_2$ it has bond order 1 , $\mathop N\nolimits_2$ has three bonds between them so has bond order 3 and $\mathop O\nolimits_2$ with two bonds have bond order 2. So $\mathop N\nolimits_2$>$\mathop O\nolimits_2$ > $\mathop H\nolimits_2$. So this statement is not wrong.

B) In $CsCl$ lattice, each $Cs$ is surrounded by $\mathop {BCl}\nolimits^ -$ ions: - $CsCl$ has body centered cubic arrangement. It has coordination number 8. Thus each Cs is surrounded by $8Cl$. Hence this statement is not wrong.

C) The ionic nature of $KCl$, $\mathop {Mgcl}\nolimits_2$ and $\mathop {AlCl}\nolimits_3$ follows the order $KCl$ >$\mathop {Mgcl}\nolimits_2$ > $\mathop {AlCl}\nolimits_3$
:- potassium has 1 electron in its outer shell as its atomic mass is 19 so electronic configuration 2,8,8,1 so has 1 unit charge. Magnesium has 2 unit charge and aluminum has 3 unit charge. So the order should be reversed $KCl$ >$\mathop {Mgcl}\nolimits_2$ > $\mathop {AlCl}\nolimits_3$. Hence this option is not correct.

D] The central atom of $\mathop {PF}\nolimits_5$, $\mathop {ClF}\nolimits_5$, and $\mathop {XeF}\nolimits_2$ have $\mathop {Sp}\nolimits^3 d$ hybridization: - in $\mathop {PF}\nolimits_5$ it involves three p one s and one d orbital thus have sp3d hybridization. In $\mathop {ClF}\nolimits_5$ it involves 2 lone pair and three bonds and in $\mathop {XeF}\nolimits_2$ three lone pair and two bond pair so have $\mathop {Sp}\nolimits^3 d$ configuration. So, this option is wrong as this statement is correct.

Note: When charge on an atom increases it becomes more ionic. The charge depends on the valence shell electrons. Potassium has 1 electron in its outer shell as its atomic mass is 19 so electronic configuration 2,8,8,1 so has 1 unit charge. Magnesium has 2 unit charge as atomic number 12 and configuration 2,8,2 so it can donate 2 electrons and aluminum has 3 unit charge.