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Chemistry Question on coordination compounds

Which one of the following is an inner orbital complex as well as diamagnetic in behaviour? (At. no. of Zn = 30, Cr = 24, Co = 27, Ni = 28)

A

[Zn(NH3)6]2+[Zn(NH_3)_6]^{2+}

B

[Cr(NH3)6]3+[Cr(NH_3)_6]^{3+}

C

[Co(NH3)6]3+[Co(NH_3)_6]^{3+}

D

[Ni(NH3)6]2+[Ni (NH_3)_6]^{2+}

Answer

[Co(NH3)6]3+[Co(NH_3)_6]^{3+}

Explanation

Solution

In [Co(NH3)6]3+[Co(NH_3)_6]^{3+}, oxidation state of Co=+3Co = +3 and its coordination number is six.
27Co=1s2,2s22p6,3s23p63d7,4s2_{27}Co = 1s^2, 2s^2 2p^6, 3s^2 3p^6 3d^7,4s^2
Co3+=1s2,2s22p6,3s23p63d6Co^{3+} = 1s^2, 2s^2 2p^6, 3s^2 3p^6 3d^6
[Co(NH3)6]3+[Co (NH_3)_6 ]^{3+} is an inner orbital complex as well as diamagnetic in behaviour (due to absence of unpaired electrons).
[Zn(NH3)6]2+→sp3d2[Zn(NH_3)_6]^{2+} \rightarrow sp^3 d^2 hybridisation (outer orbital and diamagnetic).
[Cr(NH3)6]3+→d2sp3[Cr(NH_3)_6]^{3+} \rightarrow d^2 sp^3 hybridisation (inner orbital and paramagnetic).