Question

Which one of the following is a correct set?

• A. $H_2O, Sp^3$, angular
• B. $BCl_3, Sp^3$,angular
• C. $NH^+_4, dsp^2$, square planar
• D. $CH_4, dsp^2$ tetrahedral

Answer 1

Answer: (A)

$H_2O, Sp^3$, angular

Answer 2

Molecule
$bp + Ip$
Hybridisation
Shape

$H_2O$
$2+2$
$sp^3$
angular

$BCl_3$
$3+0$
$sp^2$
trigonal planar

$NH^+_4$
$4+0$
$sp^3$
tetrahedral

$CH_4$
$4+0$
$sp^3$
tetrahedral