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Chemistry Question on coordination compounds

Which one of the following has a square planar geometry (At nos.: Fe = 26, Co = 27, Ni = 28, Pt = 78)

A

[PtCl4]2−[Pt Cl_4]^{2-}

B

[CoCl4]2−[CoCl_4]^{2-}

C

[FeCl4]2−[FeCl_4]^{2-}

D

[NiCl4]2−[NiCl_4]^{2-}

Answer

[PtCl4]2−[Pt Cl_4]^{2-}

Explanation

Solution

As Cl−Cl^- is weak field ligand so no pairing up. Hence it is sp3sp^3 hybridized giving tetrahedral geometry. Due to Cl−Cl^-, back pairing is not observed so it will be sp3sp^3 hybridized giving tetrahedral geometry. Because weak ligand, back pairing is not observed so it will be sp3sp^3 i.e. tetrahedral geometry. All the complexes of Pt2+Pt^{2+} are square planar including those with weak field ligand such as halide ions thus (4) is correct.