Question

Which one of the following compounds has $sp^2-$ hybridisation?

• A. $CO_2$
• B. $SO_2$
• C. $N_2O$
• D. CO

Answer 1

Answer: (B)

$SO_2$

Answer 2

The correct option is:(B): $SO_2$.

Sulphur in $SO_2$, is $sp^2$-hybridised.
Electron pair = 2 ($\sigma$-bonds) + 1 (lone pair) = 3
Hybridisation = $sp^2$
Carbon in $CO_2$ is sp-hybridised, N in $N_2O$ is sp-hybridised,
carbon in CO is .sp-hybridised.