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Question: Which one of the following compounds forms a quaternary salt on reacting with an excess of methyl io...

Which one of the following compounds forms a quaternary salt on reacting with an excess of methyl iodide?
(A) C2H5OCH3{{C}_{2}}{{H}_{5}}OC{{H}_{3}}
(B) (CH3)2CHOC2H5{{(C{{H}_{3}})}_{2}}CHO{{C}_{2}}{{H}_{5}}
(C) C6H5NH2{{C}_{6}}{{H}_{5}}N{{H}_{2}}
(D) C6H5NO2{{C}_{6}}{{H}_{5}}N{{O}_{2}}

Explanation

Solution

An important class of organic compound derived by replacing one or more hydrogen atoms of NH3N{{H}_{3}} a molecule with alkyl or aryl groups are amines. The amines are named as alkamines according to IUPAC nomenclature. NH2-N{{H}_{2}} the functional group attached to alkyl groups are named as alkyl amines and the same attached to the benzene ring named as arylamines.

Complete step by step solution:
Regarding the derivatives of ammonia in which one, two, or three hydrogen atoms are replaced by alkyl or aryl group formed amines.
If one H atom replaces with alkyl group in ammonia forms primary amine; RNH2(10)RN{{H}_{2}}({{1}^{0}})
If two H atoms replaced with alkyl groups in ammonia forms secondary amine; R2NH(20){{R}_{2}}NH({{2}^{0}})
If three H atoms replaced with alkyl groups in ammonia forms tertiary amine; R3N(30){{R}_{3}}N({{3}^{0}})
One lone pair of electrons of nitrogen atom contains primary amine. So, primary amine acts as a strong nucleophile, and hydrogen atoms on nitrogen are easily replaceable. Hence, primary amines are easily reacted with alkyl halides due to its nucleophilic character. If excess alkyl halides react with a primary amine, one amine molecule can rapidly react with many alkyl halides and result in the formation of a quaternary ammonium salt.
If an excess of methyl iodide reacts with a primary amine RNH2RN{{H}_{2}} , the reaction follows:
RNH2+CH3I[RN(CH3)3]+RN{{H}_{2}}+C{{H}_{3}}I\to {{[RN{{(C{{H}_{3}})}_{3}}]}^{+}} (Quaternary ammonium salt)
Hence, primary amines are reacting with excess methyl iodide to form Quaternary ammonium salts.
Given organic compounds, C6H5NH2{{C}_{6}}{{H}_{5}}N{{H}_{2}} only belongs to a primary amine.

The correct answer is option C.

Note: The formation of Quaternary ammonium salts from primary amines reacting with an excess of alkyl halides is known as ammonolysis of alkyl halides. The disadvantage of ammonolysis yielding a mixture of a primary, secondary, tertiary, and quaternary ammonium salt. However, primary amine is obtained as a major product by taking large excess of NH3N{{H}_{3}} , and the order of reactivity of halides with amines is RI>RBr>RCl.