Question

Which one is soluble in dilute HCl?
A.$AgN{O_3}$
B.$Pb{(N{O_3})_2}$
C.$H{g_2}{(N{O_3})_2}$
D.$Cu{(N{O_3})_2}$

Answer 1

We have to know that hydrochloric acid is a chemical compound with chemical formula, $HCl$ . And it contains non- reactive and non- corrosive chloride ions. The density, pH, melting point and boiling point of hydrochloric acid may vary with respect to its concentration. And it is a colorless solution having a pungent smell which is considered in the group of strong acids.

Complete answer:
We also remember that the silver nitrate is a chemical compound with formula, $AgN{O_3}$. When the silver nitrate is reacted with hydrochloric acid, there is a formation of a precipitate corresponding to its chloride, which is silver chloride. Therefore, silver nitrate is insoluble in silver nitrate. Hence, option (A) is incorrect.
When the lead chloride is reacting with hydrochloric acid, there is a formation of white precipitate which is lead chloride. Thus, lead chloride is insoluble in $HCl$ . Hence, the option (B) is incorrect.
When mercuric nitrate is reacted with hydrochloric acid, it will form mercuric chloride. Thus it is insoluble in HCl. Hence, option (C) is incorrect.
Copper (I) nitrate is a chemical compound having the formula, $Cu{(N{O_3})_2}$. Among these compounds, $Cu{(N{O_3})_2}$ is soluble in hydrochloric acid. And there is no reaction that takes place while adding copper nitrate into HCl.

Hence, the option (D) is correct.

Note:
Among these options, only copper (I) nitrate is soluble in hydrochloric acid. It is an inorganic compound which is soluble in $HCl$ , water, ethanol, ammonia etc. But other three solutions are reacted with hydrochloric acid and there is a formation of respective chloride as precipitate. But when $Cu{(N{O_3})_2}$ adds in $HCl$ , there is no reaction.