Question

Which one amongst the following pairs of ions cannot be separated by $H_2 S$ in dilute HCl ?

• A. $Bi^{3+} , Sn^{4+}$
• B. $Al^{3+} , Hg^{2+}$
• C. $Zn^{2+} , Cu^{2+}$
• D. $Ni^{2+} , Cu^{2+}$

Answer 1

Answer: (A)

$Bi^{3+} , Sn^{4+}$

Answer 2

The correct answer is A:$Bi^{3+},Sn^{4+}$
Both $Bi^{3+}$ and $Sn^{4+}$ belongs to same analytical group II.They cannot be seperated by $H_2S$ in dilute $HCL$.