Question

Which of these particle having the same kinetic energy has the largest de Broglie wavelength?

• A. Electron
• B. Alpha particle
• C. Proton
• D. Neutron

Answer 1

Answer: (A)

Electron

Answer 2

: As $\lambda = \frac{h}{\sqrt{2mK}}$

So $\lambda \propto \frac{1}{\sqrt{m}}$

Out of the given particles m is least for electron, therefore electron has the largest value of de Broglie wavelength