Question

Which of these ions will have a 0 crystal field splitting energy in an octahedral complex?
A) $F{e^{3 + }}$ in a low-spin system
B) $F{e^{3 + }}$ in a high-spin system
C) $C{r^{3 + }}\;$ in a low-spin system
D) $C{r^{3 + }}\;$ in a high-spin system

Answer 1

The crystal area stabilization electricity (CFSE) is the steadiness that effects by putting a transition metal ion withinside the crystal area generated through a fixed of ligands. It arises because of the truth that after the d orbitals are cut up in a ligand area, a number of them come to be decreasing in electricity than before.

Complete answer:
$F{e^{3 + }}$→ excessive spin
Right from the start, we can dispose of options (A) and (C) due to the fact that one's ions shape a low spin complicated.
Now, I will no longer move into an excessive amount of elements, the approximately crystal area concept is popular due to the fact I expect you are acquainted with it.
So, you realize that transition metal ions positioned in symmetric fields have degenerated orbitals which can be better in electricity than they could have been in a remote cation.
When you locate the sort of cation in an area with octahedral symmetry, the 5 degenerate orbitals will cut up into two orbitals, which can be better in electricity, and three orbitals, which can be decreased in electricity.
The crystal area stabilization electricity, or CFSE, Δ, is described as the steadiness received through the ion after putting it in a crystal area.
The concept right here is that electrons positioned withinside the orbitals will boom the steadiness of the ion due to the fact those orbitals are decreasing in electricity than the degenerate-orbitals.
On the opposite hand, electrons positioned withinside the orbitals will lessen the steadiness of the ion due to the fact the orbitals are better in electricity than the degenerate orbitals.
A low area complicated is characterized through the truth that the electrons determined withinside the d-orbitals are all positioned withinside the decrease electricity orbitals. In this way, the CFSE for such an ion cannot be identical to 0, because the ion is gaining balance relative to the preliminary electricity stage of the d-orbitals.

Note:
However, an excessive spin complicated has the capability of getting a 0 CFSE if the boom in balance because of the electrons being positioned withinside the orbitals is canceled out through the lower balance because of electrons being positioned withinside the orbitals.