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Question: Which of the sets of species have the same hybridization state but different shapes? A.\[NO_2^ + ,...

Which of the sets of species have the same hybridization state but different shapes?
A.NO2+,NO2,NO2NO_2^ + ,N{O_2},NO_2^ -
B.ClO4,SF4,XeF4ClO_4^ - ,S{F_4},Xe{F_4}
C.NH4+,H3O+,OF2NH_4^ + ,{H_3}{O^ + },O{F_2}
D.SO42,PO43,ClO4SO_4^{ - 2},PO_4^{ - 3},ClO_4^ -

Explanation

Solution

The formation of new hybrid orbital by the mixing of atomic orbital is known as hybridization. And the energy, shape etc. of the hybrid orbital may be different. The hybridization is in different types which is sp,sp2,sp3,sp2dsp,s{p^2},s{p^3},s{p^2}d , etc. In the case of sp hybridization, there is one s orbital and one p orbital. And some compounds have the same hybridization but the shape is different.

Complete answer:
In this case, NO2+,NO2,NO2NO_2^ + ,N{O_2},NO_2^ - have different hybridization as well as different shapes. The hybridization of NO2+,NO2,NO2NO_2^ + ,N{O_2},NO_2^ - is sp,sp2,sp2sp,s{p^2},s{p^2} respectively and the shape of NO2+NO_2^ + is linear, NO2N{O_2} is bent and NO2NO_2^ - is trigonal planar. Hence, option (A) is incorrect.
The hybridization and shape of ClO4,SF4,XeF4ClO_4^ - ,S{F_4},Xe{F_4} is different. The hybridization of ClO4,SF4,XeF4ClO_4^ - ,S{F_4},Xe{F_4} is sp3,sp3d,sp3d2s{p^3},s{p^3}d,s{p^3}{d^2} respectively and the shape of ClO4ClO_4^ - is tetrahedral, SF4S{F_4} is trigonal bipyramidal and XeF4Xe{F_4} is square planar. Hence, the option (B) is incorrect.
The hybridization of NH4+,H3O+,OF2NH_4^ + ,{H_3}{O^ + },O{F_2} is the same but it has different shapes. These all three compounds have sp3s{p^3} hybridization. But the shape of NH4+NH_4^ + is tetrahedral, H3O+{H_3}{O^ + } is pyramidal and the shape of OF2O{F_2} is bent. Let’s draw the structure of these compounds,

The hybridization and shape of SO42,PO43,ClO4SO_4^{ - 2},PO_4^{ - 3},ClO_4^ - is different. Hence, the option (D) is correct.

Note:
Among the given compounds, NH4+,H3O+,OF2NH_4^ + ,{H_3}{O^ + },O{F_2} have the same hybridization and different shape. And the hybridization issp3s{p^3}. The ammonium ion contains four bonding orbitals and the hydronium ion contains one lone pair of electrons. And the oxygen difluoride has two bond pairs and two lone pairs. But, the remaining compound pairs have different hybridization and shapes.