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Question

Chemistry Question on Alcohols, Phenols and Ethers

Which of the following will not form a yellow precipitate on heating with an alkaline solution of iodine?

A

CH3CH(OH)CH3CH_3CH(OH)CH_3

B

CH3CH2CH(OH)CH3CH_3 CH_2 CH(OH)CH_3

C

CH3OHCH_3 OH

D

CH3CH2OHCH_3 CH_2 OH

Answer

CH3OHCH_3 OH

Explanation

Solution

An organic compound form yellow precipitate of iodoform with I2{{I}_{2}} in presence of alkali, if it hasCH3CO\text{C}{{\text{H}}_{\text{3}}}\text{CO} group directly or it has CH3CH  OHC{{H}_{3}}-\underset{\begin{smallmatrix} | \\\ OH \end{smallmatrix}}{\overset{\begin{smallmatrix} H \\\ | \end{smallmatrix}}{\mathop{C}}}\, group CH3CH(OH)CH3+l2 NaoH CH3COCH3\text{C}{{\text{H}}_{\text{3}}}\text{CH}\left( \text{OH} \right)\text{C}{{\text{H}}_{\text{3}}}+{{\text{l}}_{\text{2}}}\text{ }\xrightarrow{\text{NaoH}}\text{ C}{{\text{H}}_{\text{3}}}\text{COC}{{\text{H}}_{\text{3}}} + 2HI+3NaI+CH3COONa+3H2O CH3COCH3+3I2+4NaOHCHI3yellow ppt. \begin{aligned} & \,\,\,\,\,\,\,\,\,\,+\text{ }2HI+3NaI+C{{H}_{3}}COONa+\underset{{}}{\mathop{3{{H}_{2}}O}}\, \\\ & C{{H}_{3}}COC{{H}_{3}}+3{{I}_{2}}+4NaOH\xrightarrow{{}}\underset{\begin{smallmatrix} \text{yellow} \\\ \text{ppt}\text{.} \end{smallmatrix}}{\mathop{CH{{I}_{3}}}}\,\downarrow \\\ \end{aligned} + 3NaI+CH3COONa+3H2O+\text{ }3NaI+C{{H}_{3}}COONa+3{{H}_{2}}O CH3CH2CH(OH) CH3+I2C{{H}_{3}}C{{H}_{2}}CH\left( OH \right)\text{ }C{{H}_{3}}+{{I}_{2}}\xrightarrow[{}]{{}} CH3CH2COCH3+2HIEthylmethylketone\underset{Ethyl\,methyl\,ketone}{\mathop{C{{H}_{3}}C{{H}_{2}}\underset{\underset{O}{\mathop{||}}\,}{\mathop{C}}\,C{{H}_{3}}+2HI}}\, It gives iodoform test. CH3CH2COCH3+3l2+4NaOH \text{C}{{\text{H}}_{\text{3}}}\text{C}{{\text{H}}_{\text{2}}}\underset{\underset{\text{O}}{\mathop{||}}\,}{\mathop{\text{C}}}\,\text{C}{{\text{H}}_{\text{3}}}+\text{3}{{\text{l}}_{\text{2}}}+\text{4NaOH }\to CHI3Yellowppt.+3NaI+CH3CH2COONa+3H2O\underset{\text{Yellow}\,\text{ppt}\text{.}}{\mathop{\text{CH}{{\text{I}}_{\text{3}}}}}\,\downarrow +\text{3NaI+C}{{\text{H}}_{\text{3}}}\text{C}{{\text{H}}_{\text{2}}}\text{COONa+3}{{\text{H}}_{\text{2}}}\text{O} CH3OH+12  HCHO+2HI\text{C}{{\text{H}}_{\text{3}}}\text{OH}+{{\text{1}}_{\text{2}}}\text{ }\xrightarrow{{}}\text{ HCHO}+\text{2HI} It does not have methyl ketonic group, so it does not give yellow ppt. with I2{{\text{I}}_{\text{2}}} in presence of alkali. CH3CH2OH+12  CH3COH+2HI\text{C}{{\text{H}}_{\text{3}}}\text{C}{{\text{H}}_{\text{2}}}\text{OH}+{{\text{1}}_{\text{2}}}\xrightarrow{\text{ }}\text{ C}{{\text{H}}_{\text{3}}}\underset{\underset{\text{O}}{\mathop{||}}\,}{\mathop{\text{C}}}\,\text{H}+\text{2HI} It gives iodoform test. CH3COH+3I2+4NaOH CHl3Yellowppt.\text{C}{{\text{H}}_{\text{3}}}\underset{\underset{\text{O}}{\mathop{||}}\,}{\mathop{\text{C}}}\,\text{H}+\text{3}{{\text{I}}_{\text{2}}}+\text{4NaOH }\xrightarrow{{}}\underset{\text{Yellow}\,\text{ppt}\text{.}}{\mathop{\text{CH}{{\text{l}}_{\text{3}}}}}\, +HCOONa+3NaI+2H2O+HCOONa+3NaI+2{{H}_{2}}O