Solveeit Logo
Login

Question

Question: Which of the following will give the maximum number of isomers? a.) \[{{[Co{{(py)}_{3}}{{(N{{H}_{3...

Which of the following will give the maximum number of isomers?
a.) [Co(py)3(NH3)3]3+{{[Co{{(py)}_{3}}{{(N{{H}_{3}})}_{3}}]}^{3+}}
b.) [Ni(en)(NH3)4]2+{{[Ni(en){{(N{{H}_{3}})}_{4}}]}^{2+}}
c.) [Fe(C2O4)(en)2]2−{{[Fe({{C}_{2}}{{O}_{4}}){{(en)}_{2}}]}^{2-}}
d.) [Co(NO2)2(NH3)4]+{{[Co{{(N{{O}_{2}})}_{2}}{{(N{{H}_{3}})}_{4}}]}^{+}}

Explanation

Solution

Isomers are the two molecules which have the same molecular formula but differ structurally. Hence, isomers contain the same number of atoms, but the arrangement of atoms differs. Properties of the isomers are going to change due to difference in the structure.

Complete step by step solution:
We have to find which coordination complex forms the maximum numbers of isomers from the given options.
Coming to given options. Option A. [Co(py)3(NH3)3]3+{{[Co{{(py)}_{3}}{{(N{{H}_{3}})}_{3}}]}^{3+}}

There are three geometrical isomers for option A.
Coming to option B, [Ni(en)(NH3)4]2+{{[Ni(en){{(N{{H}_{3}})}_{4}}]}^{2+}}. This complex won’t show any geometrical isomerism due to presence of ethylene diamine ligand (en). Ethylene diamine is a bidentate ligand. It won’t allow the molecule to rotate freely. So, option B is not the correct answer.
Coming to option C, [Fe(C2O4)(en)2]2−{{[Fe({{C}_{2}}{{O}_{4}}){{(en)}_{2}}]}^{2-}}. This complex won’t show any geometrical isomerism due to presence of ethylene diamine ligand (en) and oxalate ligands. Ethylene diamine and oxalate ligands are bidentate ligands. They won’t allow the molecule to rotate freely. So, option C is not the correct answer.
Coming to option D, [Co(NO2)2(NH3)4]+{{[Co{{(N{{O}_{2}})}_{2}}{{(N{{H}_{3}})}_{4}}]}^{+}}. It shows geometrical isomerism and linkage isomers. First we discuss geometrical isomerism.

The option D shows three geometrical isomers.
Coming to linkage isomerism.
The Nitro ligand attached to metal in two ways. In the first way through nitrogen it attaches to metal.

In the second way it attaches through oxygen,

Totally [Co(NO2)2(NH3)4]+{{[Co{{(N{{O}_{2}})}_{2}}{{(N{{H}_{3}})}_{4}}]}^{+}} forms five isomers.
There [Co(NO2)2(NH3)4]+{{[Co{{(N{{O}_{2}})}_{2}}{{(N{{H}_{3}})}_{4}}]}^{+}}has maximum number of isomers among the given options.

So, the correct option is D.

Note: The possible number of isomers of a given coordination compound is going to depend on the number of geometrical isomers it forms and number of linkage isomers are going to exhibit by the given coordination complex.