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Question: Which of the following will exhibit maximum ionic conductivity? A. \({{K}_{4}}[Fe{{(CN)}_{6}}]\) ...

Which of the following will exhibit maximum ionic conductivity?
A. K4[Fe(CN)6]{{K}_{4}}[Fe{{(CN)}_{6}}]
B. [Co(NH3)6]Cl3[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}
C. [Cu(NH3)4]Cl2[Cu{{(N{{H}_{3}})}_{4}}]C{{l}_{2}}
D. [Ni(CO)4][Ni{{(CO)}_{4}}]

Explanation

Solution

The molar conductivity of a coordination compound is going to depend on the number of ions produced by the respective coordination compound when it is dissolved in water. If the coordination compound forms a high number of ions after adding to the water then the molar conductivity of the respective compound will be high.

Complete step by step answer:
- In the question, it is asked to find the coordination compound which exhibits maximum molar conductivity among the given options.
- Coming to the given options. Option A, K4[Fe(CN)6]{{K}_{4}}[Fe{{(CN)}_{6}}].
-The compound K4[Fe(CN)6]{{K}_{4}}[Fe{{(CN)}_{6}}] dissolves in water and forms the ions and we can see them in the below chemical equation.
K4[Fe(CN)6]→4K++[Fe(CN)6]4−{{K}_{4}}[Fe{{(CN)}_{6}}]\to 4{{K}^{+}}+{{[Fe{{(CN)}_{6}}]}^{4-}}
- In the above chemical equation we can see clearly that there are five ions formed after dissociation of the compound K4[Fe(CN)6]{{K}_{4}}[Fe{{(CN)}_{6}}].
- Coming to option B, [Co(NH3)6]Cl3[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}.
- The compound [Co(NH3)6]Cl3[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}} dissolves in water and forms the ions and we can see them in the below chemical equation.
[Co(NH3)6]Cl3→[Co(NH3)6]3++3Cl−[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}\to {{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}}+3C{{l}^{-}}
- In the above chemical equation we can see clearly that there are four ions are formed after dissociation of the compound [Co(NH3)6]Cl3[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}.
- Coming to the option C, [Cu(NH3)4]Cl2[Cu{{(N{{H}_{3}})}_{4}}]C{{l}_{2}}.
- The compound [Cu(NH3)4]Cl2[Cu{{(N{{H}_{3}})}_{4}}]C{{l}_{2}} dissolves in water and forms the ions and we can see them in the below chemical equation.
[Cu(NH3)4]Cl2→[Cu(NH3)4]2++2Cl−[Cu{{(N{{H}_{3}})}_{4}}]C{{l}_{2}}\to {{[Cu{{(N{{H}_{3}})}_{4}}]}^{2+}}+2C{{l}^{-}}
- In the above chemical equation we can see clearly that there are three ions are formed after dissociation of the compound [Cu(NH3)4]Cl2[Cu{{(N{{H}_{3}})}_{4}}]C{{l}_{2}}.
- Coming to the option D, [Ni(CO)4][Ni{{(CO)}_{4}}]. It does not dissolve in water due to the absence of the polarity nature then it will be a single molecule in water.
- There the compound A, K4[Fe(CN)6]{{K}_{4}}[Fe{{(CN)}_{6}}] shows maximum molar conductivity due to the formation of 5 ions when dissolved in water. So, the correct answer is “Option A”.

Note: The number of ions formed by a coordination compound is going to decide the molar conductivity of the particular coordination compound. The number of ions formed by a coordination compound is directly proportional to the molar conductivity of the solution.