Question

Which of the following will decolourise bromine water?
A. ${C_4}{H_6}$
B. ${C_2}{H_4}$
C. ${C_6}{H_{10}}$
D. None of these

Answer 1

We have to know that bromine water is an oxidizing, exceptional yellow-to-red combination containing diatomic bromine broken down in water. It is normally utilized as a receptive in synthetic measures of acknowledgment for substances, which respond with bromine in a watery climate with the halogenation instrument, primarily unsaturated carbon compounds.

Complete answer:
We have to know that unsaturated hydrocarbons will be hydrocarbons that have twofold or triple covalent connections between adjoining carbon particles. The expression unsaturated signifies more hydrogen particles might be added to the hydrocarbon to make it immersed.
The most well-known mixtures that respond well with bromine water are phenols, alkenes, enols, the acetyl gathering, aniline, and glucose. Likewise, bromine water is regularly used to test for the presence of an alkene, which contains a twofold covalent bond, responding with the bromine water, changing it's anything but an extreme yellow to a dreary arrangement. Bromine water is likewise, generally used to check for the presence of an aldehyde bunch in compounds. In this reaction also the shade of bromine water is changed to dismal yellow.
Ethene, butyne, and hexyne can decolourize bromine water. The bromine loses its unique red-earthy colored tone to give a dry fluid. The decoloration of bromine is frequently utilized as a test for $C - C$ twofold and triple bond.

So, the correct answer is “Option A, B and C”.

Note:
We have to see that mustard gas, a noxious gas utilized in substance fighting, can be made with the assistance of alkenes. Unsaturated hydrocarbons are very valuable natural mixtures in the assembling of plastics. Polystyrene is utilized in making egg containers, expendable cups, and other advantageous items.