Question

Which of the following will be able to show geometrical isomerism ?

• A. $MA_3B$ - Square planar
• B. $MA_2B_2$, - Tetrahedral
• C. $MABCD$ - Square planar
• D. $MABCD$ - Tetrahedral

Answer 1

Answer: (C)

$MABCD$ - Square planar

Answer 2

Tetrahedral complexes do not show geometrical isomerism because relative position of unidentate ligands attached to central metal atom are same with respect to each other.

So, options (b) and (d) are not correct.

Square planar complex $M A_{3} B$ (option (a) do not show geometrical isomerism because the possible spatial arrangement are equivalent. Squar planar complex MABCD type form three isomers (cis-trans isomerism), two of these are cis and one is trans.