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Question: Which of the following volume (V), temperature (T) plots represents the behaviour of one mole of an ...

Which of the following volume (V), temperature (T) plots represents the behaviour of one mole of an ideal gas at one room atmosphere?

(A)
(B)
(C)
(D)

Explanation

Solution

To solve this we should know to read the graph carefully at first as it gives many clues and secondly, we should know the ideal gas equation. These factors above are very important to solve this question.

Complete step by step answer:
If we carefully observe the graph we can see that in every graph there are two points marked. let (i) represent points on the y-axis and let other points be (ii).
A gas is said to be ideal gas when the gas obeys Boyle's law, Charle's law and Avagado's law that is the gas does not show any deviation from above mentioned law.
Firstly let's see what ideal gas equation is:
PV= nRT
Where, P = pressure
V = volume
n = number of moles
R = gas constant
T = temperature
If a graph is plotted between volume and temperature then the pressure is at constant (from Charles's law).
For point (i): let the volume and temperature be V1{V_1} and T1{T_1} respectively. we know that P is constant and the number of moles is equal to 1.
PV1=nRT1P{V_1} = nR{T_1} equation 1
Where, V1{V_1}= 22.4L
T1{T_1}= 273K
For point (ii): let the volume and temperature be V2{V_2} and T2{T_2} respectively. We know that P is constant and the number of moles is equal to 1.
implies PV2=nRT2P{V_2} = nR{T_2} equation 2
Where, V2{V_2}= ?
T2{T_2}= 373
We have to find the value ofV2{V_2}, because if we observe only the value of V2{V_2} is changing. So to find which one is the correct graph divide equation 1 and 2.
PV1PV2=nRT1nRT2\dfrac{{P{V_1}}}{{P{V_2}}} = \dfrac{{nR{T_1}}}{{nR{T_2}}}
As we know pressure and number of moles, gas constants are the same for both the equation 1 and 2. Therefore, they cancel out each other.
So, V1V2=T1T2\dfrac{{{V_1}}}{{{V_2}}} = \dfrac{{{T_1}}}{{{T_2}}} equation 3
Substituting value of V1{V_1},T1{T_1}and T2{T_2} in equation 3 and find V2{V_2}:
    V2=373273×22.4\implies {V_2} = \dfrac{{373}}{{273}} \times 22.4
    V2=30.6\implies {V_2} = 30.6
In the graph of Option C the V2{V_2} value is 30.6.

Thus option C is the correct answer.

Note: Always try to read the graph carefully, because that gave the biggest clue that here only the value of is V2{V_2} changing. Secondly, be thorough with Boyle's law, Charles's law and Avogadro's law as this gives the clue that which quantities among the three variable quantities (P,T,V) is constant whenever a graph is plotted between any two.