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Question: Which of the following statements is correct for the reaction, at constant temperature and pressure?...

Which of the following statements is correct for the reaction, at constant temperature and pressure?
CO(g)+12O2(g)CO2(g)CO(g) + \dfrac{1}{2}{O_2}(g) \to C{O_2}(g)
a.)ΔH=ΔU\Delta H = \Delta U
b.)ΔH<ΔU\Delta H < \Delta U
c.)ΔH>ΔU\Delta H > \Delta U
d.)None of these

Explanation

Solution

Hint : We have studied the relation between change in enthalpy and change in internal energy as-ΔH=ΔU+ΔngRT\Delta H = \Delta U + \Delta {n_g}RT
Where ΔH\Delta H is the change in enthalpy, ΔU\Delta U is the change in internal energy, Δng\Delta {n_g} is the change in gaseous moles.

Complete step by step solution :
We will first study the reaction and then see which option is our answer.
So, the reaction is:-
CO(g)+12O2(g)CO2(g)CO(g) + \dfrac{1}{2}{O_2}(g) \to C{O_2}(g)
To calculate whether the Change in enthalpy is equal to, less than or greater than the change in internal energy, we will see their relationship which is-
ΔH=ΔU+ΔngRT\Delta H = \Delta U + \Delta {n_g}RT
Let this be the 1st equation.
It can be defined that the Enthalpy of a system is the sum of internal energy and the work required to achieve its pressure and volume.
Further, the equation PV=nRT

We have change in internal energy is-
ΔU=nRΔT\Delta U = nR\Delta T
From the question, it is clear that Temperature is constant i.e. ΔT\Delta T=0
ΔU=nR(0) ΔU=0 \begin{gathered} \Delta U = nR\left( 0 \right) \\\ \Delta U = 0 \\\ \end{gathered}
Now, from the reaction we can find out value of Δng\Delta {n_g}as-
Δng=1112=(12)\Delta {n_g} = 1 - 1 - \dfrac{1}{2} = \left( { - \dfrac{1}{2}} \right)
Thus, ΔH=0+(12)RT\Delta H = 0 + \left( { - \dfrac{1}{2}} \right)RT
ΔH=(12)RT\Delta H = \left( { - \dfrac{1}{2}} \right)RT
Thus, ΔH<ΔU\Delta H < \Delta U
So, the correct answer is “Option B”.

Additional Information:
Enthalpy is an extensive property. It is directly proportional to the size of the system.
The total enthalpy of a system can not be measured directly; instead, we measure the change in enthalpy. For exothermic reactions at constant pressure, the change in enthalpy of a system is equal to the sum of energy released in the reaction, energy retained in the system and energy lost in expansion.

Note : When the temperature is constant; then change in temperature will be zero. The unit for enthalpy is Joule.