Question

Which of the following statement(s) is/are correct when a mixture of NaCI and K$_2Cr_2O_7$ is gently warmed with cone. $H_2SO_4 ?$

• A. A deep red vapours is formed
• B. Vapours when passed into NaOH solution gives a yellow solution of $Na_2CrO_4$
• C. Chlorine gas is evolved
• D. Chromyl chloride is formed

Answer 1

Answer: (D)

Chromyl chloride is formed

Answer 2

$4NaCI+K_2Cr_2O_7 +6H_2SO_4 \rightarrow \, _{Chromyl \, chloride (red \, vapour)}^{2CrO_2CI_2}$
\hspace40mm +4NaHSO_4 + 2KHSO_4 + 3H_2O
$CreO_2CI_2+4NaOH \rightarrow \, \, _{Yellow \, solution}^{Na_2CrO_4}+2NaCI+2H_2O$