Question
Chemistry Question on Chemical bonding and molecular structure
Which of the following shapes of SF4 is more stable and why?
A
(i), due to 3lp−bp repulsions at 90∘
B
(ii), due to 2lp−bp repulsion
C
Both are equally stable due to 2lp−bp repulsions
D
Both are unstable since SF4 has tetrahedral shape
Answer
(ii), due to 2lp−bp repulsion
Explanation
Solution
In structure (ii),lp−bp repulsions are minimum.