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Question

Chemistry Question on Some basic concepts of chemistry

Which of the following samples contains the smallest number of atoms ?

A

1 g of CO2(g)CO_2(g)

B

1 g of C8H18C_8H_{18}

C

l g of C2H6(g)C_2H_6(g)

D

1 g of LiF(s)

Answer

1 g of CO2(g)CO_2(g)

Explanation

Solution

(A) Molar mass of CO2=44gmol1CO_{2}=44\,g\,mol^{-1} 44gCO23×6.02×102344\,g\,CO_{2} \equiv 3 \times 6.02\times 10^{23} atoms 1g1\,g of CO2CO_{2} =2×6.02×10234=\frac{2\times6.02\times10^{23}}{4} atoms =0.068×6.02×1023=0.068\times6.02\times10^{23} atoms (B) Molar mass of C8H18=114gmol1C_{8}H_{18}=114\,g\,mol^{-1} 1g1\,g of C8H18=26×6.02×1023144C_{8}H_{18}=\frac{26\times6.02\times10^{23}}{144} atoms =0.18×6.02×1023=0.18\times6.02\times10^{23} atoms (C) Molar mass of C2H6=30gmol1C_{2}H_{6}=30\,g\,mol^{-1} 1g1\,g of C2H6=8×6.02×102330C_{2}H_{6}=\frac{8\times6.02\times10^{23}}{30} atoms =0.27×6.02×1023=0.27\times6.02\times10^{23} atoms (D) Molar mass of LiF =7×19=26=7\times19=26 1g1 g of LiF =2×6.02×102326=\frac{2\times6.02\times10^{23}}{26} atoms =0.077×6.02×1023=0.077 \times 6.02\times10^{23} atoms Clearly (A)(A) has minimum number of atoms