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Question: Which of the following ring compounds obeys Huckel’s rule? (A)- \({{C}_{4}}H_{4}^{-1}\) (B)- \(...

Which of the following ring compounds obeys Huckel’s rule?
(A)- C4H41{{C}_{4}}H_{4}^{-1}
(B)- C4H4+1{{C}_{4}}H_{4}^{+1}
(C)- C4H42{{C}_{4}}H_{4}^{-2}
(D)- C4H4{{C}_{4}}{{H}_{4}}

Explanation

Solution

Erich Huckel in 1931 proposed a condition for a compound to be aromatic popularly known as Huckel’s rule. It states that a cyclic, planar and conjugated system having (4n+2)π\pi electrons, is considered to be aromatic.

Complete answer:
Aromatic compounds must obey Huckel’s rule and contain a certain number of π\pi electrons which should be equal to 4n+2. Here, n can be zero or any other positive integer. Therefore, compounds containing2π2\pi , 6π6\pi , 10π10\pi , 14π14\pi and so on electrons are aromatic.
Let us try to find the ring compound which obeys Huckel’s rule form the above given options.
C4H41{{C}_{4}}H_{4}^{-1}
Possible ring structures with C4H41{{C}_{4}}H_{4}^{-1} are shown below:

Neither of the compounds follow Huckel’s rule. In the three-membered ring compound the total number of π\pi electrons is 4, which is not a multiple of (4n+2)π\pi . Ring compounds containing 4π4\pi electrons are anti-aromatic in nature. In the four-membered ring, there is a sp3s{{p}^{3}} hybridized tetrahedral carbon, so the ring is no longer planar. Thus, Huckel’s rule cannot be applied.
C4H4+1{{C}_{4}}H_{4}^{+1}
Possible structure for C4H4+1{{C}_{4}}H_{4}^{+1} is:

This ring is not planar as it contains a sp3s{{p}^{3}} hybridized carbon. Therefore, Huckel’s rule is not applicable.
C4H42{{C}_{4}}H_{4}^{-2}
With the given molecular formula the possible ring structure is shown below:

This ring compound contains 6π6\pi electrons which is equal to (4n+2)π\pi when n=1. Therefore, it obeys Huckel’s rule and is aromatic.
C4H4{{C}_{4}}{{H}_{4}}
Structure of C4H4{{C}_{4}}{{H}_{4}} is given as:

This cyclic compound contains 4π4\pi electrons and thus, it is antiaromatic. This compound also does not follow Huckel’s rule.
The only compound following Huckel’s rule is C4H42{{C}_{4}}H_{4}^{-2}.

Hence, the correct option is (C).

Additional information:
Compounds which lacks one or more of the four requirements, i.e. cyclic, planar, conjugated and (4n+2)π\pi electrons for aromatic; 4nπ\pi for antiaromatic, to be aromatic or antiaromatic are considered as non aromatic.
Stability of the compounds follows the following order:
Aromatic > Non-aromatic> Anti-aromatic

Note:
Carefully count the number of π\pi electrons in each compound. One lone pair of electrons is counted as 2π\pi electrons and one double bond or triple bond in a ring also contributes 2π\pi electrons.