Question

Which of the following relationship is correct for the following figure-

A.$x = y = z$
B.$x = y > z$
C.$x > 120^\circ$
D.$z < 120^\circ$

Answer 1

The given compound is known as formyl fluoride. The formyl fluoride is a chemical compound having the chemical formula CHF with molecular weight $48.02g/mol$. Here, the carbon is attached with hydrogen fluorine and oxygen atoms. And it is soluble in solvents like chlorocarbons, Freon etc. When it reacts with water, it undergoes the decomposition reaction.

Complete answer:
The bond angle of x is not equal to y and z. Hence, option (A) is incorrect.
The bond angle of x is not equal to y and angle of z is not greater than x and y. hence. Option (B) is incorrect.
The bond angle of x is greater than $120^\circ$. In formyl fluoride, the central atom is carbon which is $s{p^2}$ hybridized. Therefore the bond angle is equal to $120^\circ$. Here three different atoms are attached with carbon atoms. These three atoms have different electronegativities and bond angles. The oxygen is attached with a carbon atom by using the double bond. But the carbon – hydrogen are attached by a single bond. And the bond angle of $H - C = O$ is greater than $120^\circ$. Hence, option (C) is correct.
The fluorine and hydrogen are attached by a single bond. The electrons in a double bond will significantly repel the electrons present in the $C - H$ and $C - F$ single bond. Therefore, the $H - C - F$ is less than $120^\circ$.

Hence, option (D) is correct.

Note:
We need to know that the bond angle is the angle present between two bonds which is occupied in the same covalent species. Hence, there should be at least two bonds in that covalent species. The lone pair repulsion mainly affects the bond angle. Therefore, if the central atom contains the lone pair of electrons, the angle of the compound will decrease.