Question

Which of the following particles will experience maximum magnetic force when projected with the same velocity perpendicular to a magnetic field?
A. Electron
B. Proton
C. ${\text{H}}{{\text{e}}^{\text{ + }}}$
D. ${\text{L}}{{\text{i}}^{{\text{ + + }}}}$

Answer 1

The magnetic force is induced by the motion of charges and is a product of the electromagnetic force, one of the four fundamental forces of nature. A magnetic attraction force exists between two objects containing charge moving in the same direction.

Complete step by step answer:
The magnetic force is induced by the motion of charges is,
${\text{F = qVB}}$
Since the velocity and magnetic field are constant for all four choices, F is determined by the charge value. For proton, electron and ${\text{H}}{{\text{e}}^{\text{ + }}}$, q$= 1$
For ${\text{L}}{{\text{i}}^{{\text{ + + }}}}$ q$= 2$
So for ${\text{L}}{{\text{i}}^{{\text{ + + }}}}$maximum force is experienced.
Force on a moving charged particle,
F$= qVB\sin \theta$
Here, $F$ is the energy that has been felt. The particle's charge is $q$. The charged particle's velocity is $V$.$B$ stands for magnetic field.

Force ($F$) is only dependent on charge $q$ since velocity $V$ and magnetic field $B$ are constant, and the angle between the magnetic field and charged particle is ${90^0}$. The charge on ${\text{L}}{{\text{i}}^{{\text{ + + }}}}$ now exceeds that of an electron, proton, or${\text{H}}{{\text{e}}^{\text{ + }}}$. As a result, ${\text{L}}{{\text{i}}^{{\text{ + + }}}}$ has the greatest power. The force is proportional to the charge's magnitude $q$. So we can conclude that ${\text{L}}{{\text{i}}^{{\text{ + + }}}}$ will experience maximum magnetic force when projected with the same velocity perpendicular to a magnetic field.

Note: The force acting on a charge moving in a magnetic field is often perpendicular to the velocity as well as the field. Any force acting perpendicular to the velocity has no effect on it (or the kinetic energy).