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Question

Mathematics Question on Graphical Method of Solution of a Pair of Linear Equations

Which of the following pairs of linear equations are consistent/inconsistent? If consistent, obtain the solution graphically: (i) x+y=5x + y = 5,2x+2y=10 2x + 2y = 10 (ii)xy=8,3x3y=16 x – y = 8 , 3x – 3y = 16 (iii) 2x+y6=02x + y – 6 = 0 , 4x2y4=04x – 2y – 4 = 0 (iv) 2x2y2=0,2x – 2y – 2 = 0, 4x4y5=0 4x – 4y – 5 = 0

Answer

(i) x+y=5x + y = 5
2x+2y=102x + 2y = 10

a1a2=12,b1b2=12,c1c2=510=12\dfrac{a_1}{a_2} = \dfrac{1}{2} , \dfrac{b_1}{b_2} = \dfrac{1}{2}, \dfrac{c_1}{c_2} = \dfrac{5}{10} =\dfrac{1}{2}

Since a1a2=b1b2=c1c2\dfrac{a_1}{a_2} = \dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}

Therefore, these linear equations are coincident pairs of lines and thus have an infinite number of possible solutions. Hence, the pair of linear equations is consistent.

x+y=5,x + y = 5,
x=5yx = 5 − y

xx443322
yy112233

And

2x+2y=102x + 2y =10
x=102y2x= 10-\dfrac{2y}{2}

xx443322
yy112233

Hence, the graphic representation is as follows.

From the figure, it can be observed that these lines are overlapping each other.

Therefore, infinite solutions are possible for the given pair of equations.


**(ii) **xy=8x − y = 8
3x3y=163x − 3y = 16

a1a2=13,b1b2=13=13,c1c2=816=12\dfrac{a_1}{a_2} =\dfrac{1}{3} , \dfrac{b_1}{b_2}= \dfrac{-1}{-3} = \dfrac{1}{3}, \dfrac{c_1}{c_2} = \dfrac{8}{16} = \dfrac{1}{2}

Since,a1a2=b1b2c1c2\dfrac{a_1}{a_2} = \dfrac{b_1}{b_2} ≠ \dfrac{c_1}{c_2}

Therefore, these linear equations are parallel to each other and thus have no possible solution.

Hence, the pair of linear equations is inconsistent.


**(iii) **2x + y − 6 = 0
4x − 2y − 4 = 0

a1a2=24=12,b1b2=12,c1c2=64=32\dfrac{a_1}{a_2} = \dfrac{2}{4} =\dfrac{1}{2} , \dfrac{b_1}{b_2}= \dfrac{-1}{2} , \dfrac{c_1}{c_2} = \dfrac{-6}{-4} = \dfrac{3}{2}

Since, a1a2b1b2\dfrac{a_1}{a_2} ≠ \dfrac{b_1}{b_2}

Therefore, these linear equations are intersecting each other at one point and thus have only one possible solution.

Hence, the pair of linear equations is consistent.

2x+y6=02x + y − 6 = 0 , y=62xy = 6 − 2x ;

x012
y642

And

4x2y4=04x − 2y − 4 = 0 , y=4x42y = 4x -\dfrac{4}{2}

x123
y024

Hence, the graphic representation is as follows.

From the figure, it can be observed that these lines intersect each other at the only point i.e., (2, 2) and it is the solution for the given pair of equations.


(iv) 2x2y2=02x − 2y − 2 = 0
4x4y5=04x − 4y − 5 = 0

a1a2=24=12,b1b2=24=12,c1c2=25\dfrac{a_1}{a_2}= \dfrac{2}{4} = \dfrac{1}{2}, \dfrac{b_1}{b_2} = \dfrac{-2}{-4} = \dfrac{1}{2} , \dfrac{c_1}{c_2}=\dfrac{2}{5}

Since, a1a2=b1b2c1c2\dfrac{a_1}{a_2}= \dfrac{b_1}{b_2} ≠ \dfrac{c_1}{c_2}

Therefore, these linear equations are parallel to each other and thus have no possible solution.

Hence, the pair of linear equations is inconsistent.