Question
Mathematics Question on Graphical Method of Solution of a Pair of Linear Equations
Which of the following pairs of linear equations are consistent/inconsistent? If consistent, obtain the solution graphically: (i) x+y=5,2x+2y=10 (ii)x–y=8,3x–3y=16 (iii) 2x+y–6=0 , 4x–2y–4=0 (iv) 2x–2y–2=0, 4x–4y–5=0
(i) x+y=5
2x+2y=10
a2a1=21,b2b1=21,c2c1=105=21
Since a2a1=b2b1=c2c1
Therefore, these linear equations are coincident pairs of lines and thus have an infinite number of possible solutions. Hence, the pair of linear equations is consistent.
x+y=5,
x=5−y
x | 4 | 3 | 2 |
---|---|---|---|
y | 1 | 2 | 3 |
And
2x+2y=10
x=10−22y
x | 4 | 3 | 2 |
---|---|---|---|
y | 1 | 2 | 3 |
Hence, the graphic representation is as follows.
From the figure, it can be observed that these lines are overlapping each other.
Therefore, infinite solutions are possible for the given pair of equations.
**(ii) **x−y=8
3x−3y=16
a2a1=31,b2b1=−3−1=31,c2c1=168=21
Since,a2a1=b2b1=c2c1
Therefore, these linear equations are parallel to each other and thus have no possible solution.
Hence, the pair of linear equations is inconsistent.
**(iii) **2x + y − 6 = 0
4x − 2y − 4 = 0
a2a1=42=21,b2b1=2−1,c2c1=−4−6=23
Since, a2a1=b2b1
Therefore, these linear equations are intersecting each other at one point and thus have only one possible solution.
Hence, the pair of linear equations is consistent.
2x+y−6=0 , y=6−2x ;
x | 0 | 1 | 2 |
---|---|---|---|
y | 6 | 4 | 2 |
And
4x−2y−4=0 , y=4x−24
x | 1 | 2 | 3 |
---|---|---|---|
y | 0 | 2 | 4 |
Hence, the graphic representation is as follows.
From the figure, it can be observed that these lines intersect each other at the only point i.e., (2, 2) and it is the solution for the given pair of equations.
(iv) 2x−2y−2=0
4x−4y−5=0
a2a1=42=21,b2b1=−4−2=21,c2c1=52
Since, a2a1=b2b1=c2c1
Therefore, these linear equations are parallel to each other and thus have no possible solution.
Hence, the pair of linear equations is inconsistent.