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Question

Chemistry Question on Chemical bonding and molecular structure

Which of the following pair have identical bond order?

A

CNCN^- and NO+NO^+

B

CNCN^- and O2O^-_2

C

CNCN^- and CN+CN^+

D

NO+NO^+ and O2O^-_2

Answer

CNCN^- and NO+NO^+

Explanation

Solution

For pairs having identical bond order, have identical number of electrons

Number of electrons for CN=6+7+1=14CN ^{-}=6+7+1=14

Number of electrons for NO+=7+81=14NO ^{+}=7+8-1=14

Number of electrons for O2=8+8+1=17O _{2}^{-}=8+8+1=17

Hence, CNCN ^{-} and NO+NO ^{+} have same bond order.