Question

Which of the following orders is not correct for the decreasing order of acidic character?

• A.
• B. $\mathrm { ICH } _ { 2 } \mathrm { COOH } > \mathrm { BrCH } _ { 2 } \mathrm { COOH } > \mathrm { CICH } _ { 2 } \mathrm { COOH } >$ $\mathrm { FCH } _ { 2 } \mathrm { COOH }$
• C. $\mathrm { CCl } _ { 3 } \mathrm { COOH } > \mathrm { CHCl } _ { 2 } \mathrm { COOH } > \mathrm { CH } _ { 2 } \mathrm { ClCOOH } >$ $\mathrm { CH } _ { 3 } \mathrm { COOH }$
• D. $\mathrm { HCOOH } > \mathrm { CH } _ { 3 } \mathrm { COOH } > \mathrm { C } _ { 2 } \mathrm { H } _ { 5 } \mathrm { COOH } >$ $\left( \mathrm { CH } _ { 3 } \right) _ { 2 } \mathrm { CHCOOH }$

Answer 1

Answer: (C)

$\mathrm { CCl } _ { 3 } \mathrm { COOH } > \mathrm { CHCl } _ { 2 } \mathrm { COOH } > \mathrm { CH } _ { 2 } \mathrm { ClCOOH } >$

$\mathrm { CH } _ { 3 } \mathrm { COOH }$

Answer 2

: Both ethanal and propanal will give silver mirror test and red precipitate with Fehling’s solution. They can be differentiated by iodoform test.